X Trench Run Math //top\\ -

Assume the torpedo enters the port horizontally at speed (v), then experiences a constant vertical acceleration (a) (from the magnetic field) over a short distance (d) (the shaft length before impact).

[ h = \frac12 a t^2 ] [ d = v t ]

[ h = \frac12 a \left( \fracdv \right)^2 ] x trench run math

To hit a 2 m wide port from a horizontal offset of zero (directly above), the required vertical acceleration: Assume the torpedo enters the port horizontally at

[ P_\texthit \approx 1 - e^-0.913 \approx 1 - 0.401 \approx 0.599 \ (\text59.9%) ] x trench run math

Eliminate (t):

: