Class 10 Electricity Ncert Solutions Guide

Answer: ( H = V \times I \times t = V \times Q = 50 \times 96000 = 4.8 \times 10^6 , \text{J} )

Answer: Alloys have higher resistivity and do not oxidize easily at high temperatures.

Answer: 1 volt means 1 joule of work is done to move 1 coulomb of charge from one point to another. [ 1 , \text{V} = 1 , \text{J/C} ] class 10 electricity ncert solutions

(a) 1:2 (b) 2:1 (c) 1:4 (d) 4:1 Answer: Each R, series ( R_s = 2R ), parallel ( R_p = R/2 ) Heat ( H = V^2 t / R ) → ( H_s / H_p = R_p / R_s = (R/2) / (2R) = 1/4 ) → (c)

Answer: (i) 9 Ω = two in parallel (3 Ω) + one in series (6 Ω) (ii) 4 Ω = two in series (12 Ω) in parallel with one (6 Ω): ( 1/R = 1/12 + 1/6 = 3/12 ) → R=4 Ω Answer: ( H = V \times I \times

Answer: ( H = I^2 R t = 5^2 \times 20 \times 30 = 25 \times 20 \times 30 = 15000 , \text{J} ) In-Text Questions (Page 220) Q1. What determines the rate at which energy is delivered by a current? Answer: Electric power ( P = V \times I = I^2 R = V^2 / R )

Here are the (based on the latest NCERT textbook). What determines the rate at which energy is

(a) 100 W (b) 75 W (c) 50 W (d) 25 W Answer: Resistance ( R = V^2 / P = 220^2 / 100 = 484 , \Omega ) At 110 V: ( P = V^2 / R = 110^2 / 484 = 25 , \text{W} ) → (d)